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3 years ago

9

X^2 + 6x +15=0 solve the equation using the quadratic formula

1 answer:

gladu [14]3 years ago

6 0

I hope this helps you

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Solve and show work

Alika [10]

84 gallons/(2.8 gpm) = 30 minutes

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3 years ago

What is 1.75rounded to the nearest cent mathematics

Stels [109]

The answer is the same as the question. 1.75

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3 years ago

Help ill give you Brainliesttt ‼️‼️‼️‼️‼️‼️

Lesechka [4]

Answer:

Step-by-step explanation:

+ we take t- number of tickets and each ticket cost $7.

So t is too the number of people who buy tickets, then

$0\leq t\leq 200$

A) We can calculate the amount of money: M= 7t where $0\leq t\leq 200$

B) The domain for t is $0\leq t\leq 200$ , t is an integer.

C) The range for the amount M:

$0*7\leq M\leq 200*7\\0\leq M\leq 1400$

5 0

3 years ago

⦁ Write an equation of a line in slope intercept form (y = mx + b) with slope 1/3 going through the point (-6, 2). Show your wor

Zepler [3.9K]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y-2=\cfrac{1}{3}(x+6)\implies y-2=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+4$

3 0

2 years ago

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

4 0

3 years ago