Answer:
Option C, Intrapleural pressure is less than intrapulmonary pressure
Explanation:
During inspiration, the air enters the lungs due to lower pressure in the intrapulmonary or intra-alveolar than the atmospheric pressure. During quite respiration, the intrapulmonary pressure reduces to a pressure that is 3 mm Hg lower than that of atmospheric pressure. During quiet expiration, the intrapulmonary pressure rises up to a pressure that is 3 mm Hg higher than that of atmospheric pressure. This leads to lack of air in the intrapleural space thereby producing intrapleural pressure which is lesser than that of intrapulmonary pressure.
This difference in pressure (i.e higher pressure with in the lungs than the atmosphere) causes lungs to remain attached to the chest wall and hence looks inflated.
Hence, option C is correct
<span>The answer is that cell will shrink.</span>
<span>If you put an animal cell in a hypertonic solution means that concentration of the solutes is greater outside the cell, in the solution, than in the cell. Consequently,</span> the water concentration of the cell's cytoplasm is higher than that of the hypertonic solution. Since the aim is to balance water concentration on the inside and outside of the cell, the water will exit the cell. The cell will lose water and, consequently, will shrink in size.
