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elena55 [62]
3 years ago
15

X - 4 = 9 Can someone please help me

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:

x=13

Step-by-step explanation:

isolate the x by adding4 to each side of the equation

x - 4 = 9

 + 4 =+ 4

and then the -4 cancels out and you get x = 13

I hope this helps :)

natka813 [3]3 years ago
6 0

Answer:

13!

Step-by-step explanation:

add 14 both sides you should add up to 13 from 9 + 4 and then 13 divided by 1

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What is 400,000 times 200 in scientific notation
aniked [119]

If you move the decimal point left until it is just to the right of the most-significant digit, the number of places you moved it is the power of ten that your new number is multiplied by.

400,000=4\times 10^{5}\\200=2\times 10^{2}

Then multiplication can proceed in the usual way, taking into account the rules of exponents.

4\cdot 10^{5}\times 2\cdot 10^{2}=8\cdot 10^{(5+2)}\\\\=8\cdot 10^{7}

8 0
3 years ago
Read 2 more answers
6 more than the product of a number x and 5 is 21
fgiga [73]

Answer:

x = 3

Step-by-step explanation:

6 <em>+</em><em> </em><em>5</em><em>x</em><em> </em>= 21

<em>5</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em>

<em>x</em><em> </em><em>=</em><em> </em><em>3</em>

I hope this helps

:)

4 0
2 years ago
This is due today plz help
dybincka [34]

Answer:

how to answer it where is the direction

3 0
2 years ago
Which expression is equivalent to -4(x-2)-1/2(2x+6)
Alexus [3.1K]

Answer:

-5x+5

Step-by-step explanation:

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3 0
3 years ago
The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi
pshichka [43]

Answer:

E(\bar{x}) = 28520

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

E(\bar{x}) = \mu = 28520

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689

7 0
3 years ago
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