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3 years ago

Find the value of x

Mathematics

1 answer:

Leno4ka [110]3 years ago

3 0

If both sides are supposed to be equal, then x=59

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PLEASE FIND THE SURFACE AREA ASAP

Ilya [14]

Answer:

Ok ill help but please give me a lot of credit since i took the time to do it for you!

13 x 3 = 39, 39 x 2 = 78

9 x 3 = 27, 27 x 2 = 54

9 x 13 = 117, 117 x 2 = 234

234 + 78 + 54 = 366 mm

20 x 6 = 120, 120 x 2 = 240

4 x 20 = 80, 80 x 2 = 160

6 x 4 = 24, 24 x 2 = 48

240 + 160 + 48 = 448 cm

5 x 14 = 70, 70 x 2 = 140

5 x 16 = 80, 80 x 2 = 160

14 x 16 = 224 , 224 x 2 = 448

448 + 160 + 140 = 748 m

4 x 14 = 56, 56 x 2 = 112

17 x 4 = 68, 68 x 2 = 136

14 x 17 = 238, 238 x 2 = 476

476 + 112 + 136 = 724 ft

4 x 13 = 52, 52 x 2 = 104

13 x 19 = 247, 247 x 2 = 494

19 x 4 = 76, 76 x 2 = 152

104 + 494 + 152 = 750 in

14 x 9 = 126, 126 x 2 = 252

9 x 3 = 27, 27 x 2 = 54

3 x 14 = 42, 42 x 2 = 84

252 + 54 + 84 = 390 mm

7 x 12 = 84, 84 x 2 = 168

12 x 2 = 24, 24 x 2 = 48

2 x 7 = 14, 14 x 2 = 28

168 + 48 + 28 = 244 cm

6 x 4 = 24, 24 x 2 = 48

6 x 13 = 78, 78 x 2 = 156

4 x 13 = 52, 52 x 2 = 104

48 + 156 + 104 = 308 in

8 x 15 = 120, 120 x 2 = 240

4 x 15 = 60, 60 x 2 = 120

8 x 4 = 32, 32 x 2 = 64

240 + 120 + 64 = 424 ft

Please try to do 10 by yourself, thank you. Brainliest please.

6 0

3 years ago

Karen notices that segment BC and segment EF are congruent in the image below:

LenaWriter [7]

Answer:

Givens:

$A(-2;2) \ B(-2;4) \ C(0;3) \ D(2;1) \ E(2;3) \ F(0;2)$
$BC \cong EF$
$\angle C \cong \angle F$

Using this information we could recur to SAS postulate to demonstrate the congruence of this pair of triangles. We already have one side and one angle congruent, we just need to demonstrate that $AC \cong DF$ , that will prove the complete congruence.

So, based on the given coordinates, we're able to calculate the length of each side and find if they are the same. We use this formula:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\d_{AC} =\sqrt{(0-(-2))^{2}+(3-2)^{2}}=\sqrt{4+1}=\sqrt{5}\\\\\d_{DF} =\sqrt{(0-2)^{2}+(2-1)^{2}}=\sqrt{4+1}=\sqrt{5}$