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Komok [63]
2 years ago
6

Plz help me solve and show your work.

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
7 0

Hi there!

\large\boxed{h = \frac{15x}{y}}

Recall the volume of a pyramid is:

V = 1/3(bh)

We are given the volume and side length of the base. Find the area of the base:

A = s²

A = (5xy²)² = 25x²y⁴

Plug in the solved for base:

125x³y³ = 1/3(25x²y⁴)h

To isolate for h, begin by multiplying both sides by 3:

375x³y³ = (25x²y⁴)h

Divide both sides by 25x²y⁴. Use the following exponent property:

xᵃ / xᵇ = xᵃ⁻ᵇ

Thus:

375x³y³ / 25x²4⁴ = 15x/y.

The height must be equal to:

h = \frac{15x}{y}

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Answer:

Assuming I'm one of the 36 English speakers and the other 24 speak Spanish for illustration purposes.  The problem can be modeled as 59 marbles with 35 E and 24 S marbles as N = 59 possible outcomes = n(E) + n(S) = 35 + 24.

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I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three.  This one is p(E >= 1|4 attempts).  We can trace out a probability tree to identify those branches that contain at least one E event.  So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =  

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619   ANS.  In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

00

Step-by-step explanation:

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