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Komok [63]
3 years ago
6

Plz help me solve and show your work.

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0

Hi there!

\large\boxed{h = \frac{15x}{y}}

Recall the volume of a pyramid is:

V = 1/3(bh)

We are given the volume and side length of the base. Find the area of the base:

A = s²

A = (5xy²)² = 25x²y⁴

Plug in the solved for base:

125x³y³ = 1/3(25x²y⁴)h

To isolate for h, begin by multiplying both sides by 3:

375x³y³ = (25x²y⁴)h

Divide both sides by 25x²y⁴. Use the following exponent property:

xᵃ / xᵇ = xᵃ⁻ᵇ

Thus:

375x³y³ / 25x²4⁴ = 15x/y.

The height must be equal to:

h = \frac{15x}{y}

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10 divided by 5 =2 floors per second. Divide 2 by 1= 1. 1 floor  in 1 second.
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PLEASE HELP i will give brainliest:) A rectangular yard has an area of 24 meters squared. What are four possible perimeters for
kolezko [41]

Answer:

20, 22, 28, 50

Step-by-step explanation:

l+l+w+w=p

2l+2w=p

The length and width could be:

1, 1, 24, 24

2, 2, 12, 12

3, 3, 8, 8

4, 4, 6, 6

1+1+24+24= 50

2+2+12+12= 28

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4 years ago
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I think it’s 104,974
Because PEMDAS,
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Finally comes subtraction, 104,976 minus 2 = 104,974
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Explain how you decided where to place the decimal in the quotients for 152÷10, 152÷100,152÷1000
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7 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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