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skad [1K]
3 years ago
6

I only need help on the one that are mark blue

Mathematics
1 answer:
Oxana [17]3 years ago
4 0
1. (54/9)6 equation
     6 x 6
       36 answer
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Which expression is equivalent to (StartFraction a Superscript negative 8 Baseline b Over a Superscript negative 5 Baseline b cu
Eddi Din [679]

Answer:

its A, a^9 b^6

Step-by-step explanation:

right on edge 2020

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2 years ago
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Is 10 yards smaller than 360 inches
Nikolay [14]
No 10 yards equals 360 inches
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3 years ago
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From the beginning of the day the temperature rose 15° so that by 4 pm it was 87°. What was the temperature at the start of the
zubka84 [21]
Your answer is A, 72°.
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3 years ago
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Amy received a $80 gift card for a coffee store. She used it in buying some coffee that cost $8.24 per pound. After buying the c
SVEN [57.7K]

Answer:

5 pounds

Step-by-step explanation:

Given that:

Amount of gift card = $80

Cost of coffee per pound = $8.24

Amount left in the card = $38.80

To find:

Number of pounds of coffee bought = ?

Solution:

Let the number of pounds of the coffee bought = x pounds

Cost of 1 pound = $8.24

Cost of x pounds = $8.24 \times x

Writing the equation as per question statement:

80 - 8.24x = 38.80\\\Rightarrow 80 - 38.80 = 8.24x\\\Rightarrow  8.24x = 41.2\\\Rightarrow x = \dfrac{41.2}{8.24}\\\Rightarrow \bold{x = 5\ pounds}

Therefore, 5 pounds of coffee was bought.

3 0
3 years ago
The diagram shows the sector of a circle with the centre O and radius 6cm.
cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = \frac{\theta}{360}(\pi r^{2})

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = \frac{50}{360}(\pi )(6)^2

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = \frac{1}{2}(OP)(PN)

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = \frac{PN}{ON}

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) = \frac{OP}{ON}

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

3 0
3 years ago
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