Answer:
3/4
Step-by-step explanation:
it's for sure 3/4!!!!!
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
The awnser would be -11. A minus and a minus creates a plus so it adds up to -11
Answer:
36
Step-by-step explanation:
40 * .10 = 4
40-4 = 36
Box-and-whisker plot
We are given the box-and-whisker plot that summarizes the magnitude of earthquakes.
The minimum value of the dataset is 2,5
The maximum value of the dataset is 8.5
The range is the difference:
Range = 8.5 - 2.5 = 6
Range = 6