First you add up the red and black so see how many she has total.
45 + 60= 105
then if you need to find the probability of the red candies you put
45/ 105
then you can simplify it so it would be 8/21
45+60=105
45/105= 8/21
68
<u />x<u>90
</u> 6,120
Hope this helps :D
First convert the distance to miles
<span>9.5 × 10^12 km x 0.62 miles/km </span>
<span>= (0.62 × 9.5) x 10^12 miles </span>
<span>= 5.9 × 10^12 miles </span>
<span> we want to triple that, because it is 3 light years (not just 1): </span>
<span>3 x 5.9 × 10^12 miles </span>
<span>≈ 18 × 10^12 miles </span>
<span>≈ 1.8 × 10^13 miles </span>
<span>Next divide by the speed to get the time (in hours). </span>
<span>t = 1.8 × 10^13 miles / 17000 miles/hour </span>
<span>convert the speed to scientific notation: </span>
<span>t = 1.8 × 10^13 / 1.7 x 10^4 </span>
<span>t = (1.8 / 1.7) × (10^13 / 10^4) <-- when dividing powers with the same base, subtract the exponents </span>
<span>t ≈ 1.1 × 10^9 </span>
<span>convert that back to standard notation. </span>
<span>Answer: </span>
<span>1,100,000,000 hours (P.S. That is about 120,000 years).
Hope this helps!!!</span>
Fragment free frame processing method causes a switch to wait until the first 64 bytes of the frame have been received before forwarding the frame to the destination device
An advanced type of cut-through switching is fragment-free (runtless switching). Before making a switching choice, switches engaged in cut-through switching merely read the Ethernet frame's destination MAC address field.
- What distinguishes fragment-free switching from fast forward switching?
The latency in fast-forward mode is calculated between the first bit received and the first bit delivered. The most common cut-through switching technique is fast-forward switching. Switching without fragments: The switch stores the first 64 bytes of the frame in fragment-free switching before forwarding.
Learn more about frame here: brainly.com/question/19756844
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Answer:
10 ft
Step-by-step explanation:
