With u = <-7, 6> and v = <-4, 17>, we have
u + 3v = <-7, 6> + 3 <-4, 17> = <-7, 6> + <-12, 51> = <-19, 57>
We want to find a vector w such that
u + 3v + w = <1, 0>
Subtract u + 3v from both sides to get
w = <1, 0> - (u + 3v) = <1, 0> - <-19, 57>
w = <20, -57>
Answer:
okay this question i dont know
1st - 2/3 =π√÷
and if tiu substrate that
the answer is 12358063
you can give me the brainliest if u want
final answer-
325
So to answer you just have to substitute all the given choices into the formula and see which come out true.
2(1) - 3(-3) >_ 12
2 + 9 >_ 12
11 >_ 12
XNXOXPXEX
2(8) - 3(1) >_ 12
16 - 3 >_ 12
13 >_ 12
VYVEVSV
2(3) - 3(2) >_ 12
6 - 6 >_ 12
0 >_ 12
XNXOXPXEX
2(-2) - 3(-6) >_ 12
-4 + 18 >_ 12
14 >_ 12
VYVEVSV
2(2) - 3(3) >_ 12
4 - 9 >_ 12
-5 >_ 12
XNXOXPXEX
2(1) - 3(8) >_ 12
2 - 24 >_ 12
-22 >_ 12
XNXOXPXEX
2(-3) - 3(1) >_ 12
-6 - 3 >_ 12
-9 >_ 12
XNXOXPXEX
VYVEVSV = yes
XNXOXPXEX = nope
Answer:
Step-by-step explanation:
A quadratic in factored form is usually expressed as: 
where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as: 
. Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)
I'll use the point (1, -4) the vertex
-4 = a(1+1)(1-3)
-4 = a(2)(-2)
-4 = -4a
1 = a. So yeah the value of a is 1
So the equation is just:
