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3 years ago

Define a variablr and write an enquality to model each situation

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Let n be the number of people in the restaurant: 0 ≤ n ≤ 172
Let a be a person's age. a ≥ 35

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PLEASE HELP ME, im offering 20 points!

Liono4ka [1.6K]

Answer:

hope im right

1. 12.5 cm

2. .8 km

3. 480 cm

4. im so sorry i dont know

Step-by-step explanation:

6 0

3 years ago

If a half a gallon of milk cost $1.24 what is the cost per pint

Kaylis [27]

Answer:

$0.62

Step-by-step explanation:

1.24/2=0.62

1 gallon- 4 pint

0.5 gallon- 2 pint

5 0

3 years ago

Rewrite x - 2y = 8 using function notation.

Yanka [14]

x - 2y = 8 then it is y = 0.5x-4.

Hope I helped! ( Smiles )

8 0

4 years ago

Need help on this guys

MakcuM [25]

Answer:

pretty sure its 5

Step-by-step explanation:

8 0

3 years ago

A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati

lilavasa [31]

Answer:

The minimum average cost is $2.80 when 163 players are built

Step-by-step explanation:

Average Cost Function

We'll assume the given function as the total cost to produce x players, and NOT the average cost since that is a different definition, as shown below.

The cost C to produce x DVD/Blu- ray players is given by the equation

$C=0.03x^2-7x+800$

The Average Cost function is defined as

$\displaystyle\bar C=\frac{C}{x}$

$\displaystyle\bar C=\frac{0.03x^2-7x+800}{x}$

$\displaystyle\bar C=0.03x-7+\frac{800}{x}$

To find the extreme value of the average cost, we must take the first derivative of the function

$\displaystyle\bar C'=0.03-\frac{800}{x^2}$

Equating to 0

$\displaystyle 0.03-\frac{800}{x^2}=0$

Solving for x

$\displaystyle x=\sqrt{\frac{800}{0.03}}$

$x=163$

The second derivative is

$\displaystyle\bar C''=\frac{1600}{x^3}$

For x=163 the second derivative is positive, thus x=163 is a minimum value. Let's compute the minimum average cost

$\displaystyle\bar C(163)=0.03\cdot 163-7+\frac{800}{163}$

$\displaystyle\bar C(163)=2.80$

The minimum average cost is $2.80

5 0

3 years ago