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leva [86]
3 years ago
5

How to find if a triangle is acute or obtuse with side lengths?

Mathematics
1 answer:
elena55 [62]3 years ago
8 0
You would have to determine if<span> the following </span>lengths<span> make an </span>acute<span>, right or </span>obtuse triangle<span>. Plug in each set of </span>lengths<span> into the Pythagorean Theorem.</span>
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(2x-20) + 86 what is the the value of x
julsineya [31]
When (2x-20)+86=0
2x-20=-86
2x=-46
x=-23
6 0
3 years ago
What would my final balance be if i put $650 in the bank for 60 months with an interest rate of 6%?
Flauer [41]
Your final balance would be $2,340.

I = Prt
Percent (6%) x rate (650) x time (60 months) = 2,340

6% = 0.06

0.06 x 60 x 650 = 2,340


3 0
3 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
X=-2y+16<br> 4x+8y=32<br> substitutional equation
Dahasolnce [82]
4(-2y + 16) + 8y = 32
-8y + 64 + 8y = 32
64 = 32
Answer: no solution
5 0
2 years ago
What is the Oder of 7/10 7/8 7/12 7/9
Flauer [41]
Least to Greatest Order -

   7/12,   7/10,   7/9,   7/8
(Least)                    (Greatest)
5 0
2 years ago
Read 2 more answers
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