All categories

2 years ago

Celina built a model of a triangular pyramid. The model's height is shown in the diagram.

Mathematics

1 answer:

sergey [27]2 years ago

7 0

Answer:

12.85 / D

Step-by-step explanation:

Dont listen to him its 12.85

The formula add up to 12.85

V=Bh

96.37=7.5

7.5B/7.5=B

B stands for base or big b

so you do the same thing to the volume

96.37/7.5=12.85

You might be interested in

Need help with these two

DiKsa [7]

Am sorry I really need this point sorry again

4 0

3 years ago

Put this into slope form x/2 + 2y= 6

Inga [223]

Answer:

y=-1/4x +3

Step-by-step explanation:

x/2 + 2y = 6

Subtract x/2 from both sides

2y=-x/2 +6

Simplify by dividing by 2

y=-1/4x +3

8 0

3 years ago

Find the 13 term<br>7 la For the sequence 11,13,15,17

zaharov [31]

Well i don’t understand your question but the pattern is infinitely (+2) the next 3 terms are 19,21,23

5 0

2 years ago

(7.02) classify each sequence as arithmetic, geometric, or neither.

Digiron [165]

Answer:

geometric

arithmetic

Step-by-step explanation:

4/9,4/3,4,12,36

Multiply each term by 3 to get the next term. There is a common ratio between terms, so it geometric.

0,1,2,3,4,5,6

Add 1 to each term to get the next term. Since there is a common difference between terms, it is an arithmetic sequence.

-10,-6,-2,2,6,10

Add 4 to each term to get the next term. Since there is a common difference between terms, it is an arithmetic sequence.

6 0

3 years ago

Isabella is solving the equation 4x^2=13x-3 with the quadratic formula

laiz [17]

Answer:

x=(3,1/4)

Step-by-step explanation:

Be sure to use the formula...

$-b + or - sqrt{b^{2} - 4ac } / 2a$

- First, move all variables to one side (left) of the equation. You want one side to be equivalent to zero.

-Next, you need to find a, b, and c. This should be...

a=4

b=-13

c=3

- Knowing this, fill in these variable to go along with the formula. I cannot do this for you, as you should try it on your own. But, you should end up with the solution x= (3,1/4).

- Hope this helps! If you need a further explanation or help on any more problems please let me know, as I would be glad to help anytime.

5 0

3 years ago