Sorry I do not know I wish I could help you
Answer:
a. t*
b. (22.87, 24.53)
c. yes
Step-by-step explanation:
We have the following data:
mean = m = 23.7
standard deviation = sd = 2.15
x = 20
Thus:
a. The critical value would be t * since the value is m <30
b. whenever the mean is less than 30, the t distribution is used, for 95% confidence interval with degree of freedom = (x - 1) df
= 20 - 1
= 19
now, for this value we look in the table of t, we find that t * = 1.729
m + - t * (sd / x ^ 81/2))
replacing
23.7 + - 1.729 * (2.15 / 20 ^ (1/2))
23.7 + - 0.8312
then the inverval would be:
23.7 + 0.8312 = 24.5312
23.7 - 0.8312 = 22.8688
(22.87, 24.53)
c. yes, the interval is accurate since the mean of 23.7 is within this value
Answer:
A; ?; Line 3
Step-by-step explanation:
Question 1:
-30 divided by -6 is 5.
The negatives cancel each other out.
And 30 divided by 6 is simply 5.
Question 2:

Do the operation inside the parenthesis first:

Divide. 12 does not go into 62 evenly. 12 times 5 is 60, so the answer is 5 remainder 2:

Or in fractions:

(Was there a typo? From what you've given me, the correct answer is not listed.)
Question 3:
So we have to following steps:

The mistake is in Line 3. Danny cannot just combine 5+6(2) into 11(2). Instead, he should multiply 6(2) and then add. Thus, the correct solution is:

Answer:
4x-9
Step-by-step explanation:
6+7x-4-3x-11
Combine like terms: 7x-3x = 4x
:6-4-11 = -9
Combine them together and you get 4x-9
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Subtract 4 from 6
7
x
+2-3x-11
Subtract 3x from 7x
4x+2-11
Subtract 11 from 2
4x-9
Answer:
Step-by-step explanation:
