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zaharov [31]
3 years ago
12

Anyone know how to solve this?? Number 5!!

Mathematics
1 answer:
iragen [17]3 years ago
8 0
P=6+1+2
6+1+2=9 x 3= 27
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Ten more than half of a number is eight less than twice the number. What is the number?
Neporo4naja [7]
Ten (10) more than (+) half (\frac{1}{2}) of a number (x) is (=) eight (8) less than (-) twice (2 x ) the number (x).

\frac{1}{2}x + 10 = 2x - 8   Multiply both sides by 2
x + 20 = 4x - 16   Subtract x from both sides
20 = 3x - 16         Add 16 to both sides
36 = 3x                Divide both sides by 3
12 = x
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3 years ago
Whats 18 over 36 simplified
Genrish500 [490]
18 divide by 36 = 0.5 or 1/2.
4 0
3 years ago
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What is the missing length?<br> 10.2 cm<br> a<br> area=51 cm2
AleksAgata [21]

Answer:

a = 10 cm

Step-by-step explanation:

Area of triangle, A = 51 cm²

base, b = 10.2 cm

Let height of triangle be a cm

<em><u>Formula:-</u></em>

A=\dfrac{1}{2}\times a\times b

51=\dfrac{1}{2}\times a\times 10.2

a=\dfrac{51\times 2}{10.2}

a=10

hence, the missing length is 10 cm

4 0
3 years ago
I need help ASAP. Thank you :)
kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

m∠DFE = m∠DEF

m∠DEF = 64°

<em>sum of all the angles of a triangle = 180°</em>

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

8 0
3 years ago
Convert 2.3 radians to degree measure
zmey [24]

Answer:131.78

Step-by-step explanation:

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4 years ago
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