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zepelin [54]
3 years ago
15

point k is between points j and l if jk=xsquared -4x, kl= 3x-2, and jl= 28, write and solve an equation to find the lengths of j

k and kl
Mathematics
1 answer:
nadya68 [22]3 years ago
8 0
Jk= 18
Kl= 10

3x - 2 = 28
+2. +2
3x / 3 and 30 / 3 = 10
28-10 = 18
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Bingel [31]

Answer:

3 and 4

Step-by-step explanation:

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Next, let's look at each of the options

In this case we lack a term with x since if we solve we have a linear equation

1.    5(x+9)

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In this case if we pay attention they are being subtracted instead of multiplying, so we will not get a quadratic function

2.    (x+4) - (x+6)

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In this case we have everything we need, now let's try to solve

4.     (x-3) (x+2)

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3 years ago
A box contains 3 black pens, 7 blue pens, and 5 red pens. She pulls a red pen, puts it back, pulls a blue pen, puts it back, and
saveliy_v [14]

Answer:

7/25

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = expected outcome/total outcome

If the box contains 3 black pens, 7 blue pens, and 5 red pens, the total number of pens in the box is 3+7+5 = 15pens

Probability of pulling a red pen and replacing = 5/15 = 1/3

Probability of pulling a blue pen and replacing = 7/15

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{Note that the total number of outcome used will still be 15 since the black pen was pulled out last even though it wasn't replaced.}

P(red, then blue, then black) = 1/3×7/15×3/15

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4 0
3 years ago
suppose you have a dime, two pennies, and a quarter. one of the pennies was minted in 1976, and the other one was minted in 1992
notsponge [240]

The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

<h3>How to Solve Counting Problems?</h3>

A) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins. Let us label the dime as D, the penny as P, the quarter minted in 1976 as Q1 and the quarter minted in 1992 as Q2.

Now, if you choose one coin, you could choose either D, P, Q1, or Q2. This gives us 4 possible sets.

If you choose two coins, you choose the following sets of coins: DP, DQ1, DQ2, PQ1, PQ2, Q1Q2. This gives us 6 possible sets.

If you choose three coins, you could the following sets of coins: DPQ1, DPQ2, DQ1Q2, PQ1Q2. This gives us 4 possible sets.

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible set.

Therefore, the total number of different sets of coins you can form is 4 + 6 + 4 + 1 = 15 different sets of coins can be formed.

b) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins.

If you choose one coin you could choose either D, P, Q1, or Q2. However, since Q1 and Q2 give us the same sum, they are effectively the same set. This gives us 3 possible sums (ten cents, one cent, or twenty-five cents.)

If you choose two coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DP, DQ, PQ, Q1Q2. This gives us 4 possible sums (11 cents, 35 cents, 26 cents, or fifty cents.)

If you choose three coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DPQ, DQ1Q2, PQ1Q2. This gives us 3 possible sums (36 cents, 60 cents, or 51 cents).

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible sum (61 cents.)

Therefore, the total number of different sums of coins you can form is 3 + 4 + 3 + 1 = 11 different sums of money can be produced.

c) The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

Read more about Counting Problems at; brainly.com/question/13875198

#SPJ1

3 0
1 year ago
Find the HCF of 18 and 12
Natasha2012 [34]

Answer:

Answer is 6.

Step-by-step explanation:

I hope it's helpful!

4 0
2 years ago
Read 2 more answers
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White raven [17]

Answer:

2 cm

Step-by-step explanation:

h = 14 cm

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Diameter = 2 * r = 2 * 1 = 2  cm

6 0
3 years ago
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