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xenn [34]
2 years ago
5

If f(x)=the square root of x+12 and g(x)=2 times the square root of x, what is the value of (f-g)(144)?

Mathematics
2 answers:
notka56 [123]2 years ago
4 0
(f-g)(144) =  \sqrt{144}+12-2 \sqrt{144}  \\(f-g)(144) =  12+12-2*12 \\ (f-g)(144) =  24-24 \\ (f-g)(144) = 0
expeople1 [14]2 years ago
3 0
If (f-g)(144) plug 144 for x and g

You get f(x) = f(144) = √144 + 12 = 12 + 12 = 24

g(x) = g(144) = 2√144 = 2*12 = 24

f-g = 24-24 = 0
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For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
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Answer:

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b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

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On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

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When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

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R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

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2 years ago
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