Answer:
The solutions are:
Step-by-step explanation:
We have the following quadratic equation
We can rewrite the equation as follows
Now we use the quadratic formula to solve the equation
For an equation of the form the quadratic formula is:
In this case:
Then:
Answer:
C = 68.667°
a = 123.31 yd.
c = 114.90 yd.
Step-by-step explanation:
The missing image for the question is attached to this solution.
In the missing image, a triangle AB is given with angles A and B given to be 88° 35' and 22° 45' respectively
We are them told to find angle C and side a and c given that side b = 47.7 yd.
A = 88° 35' = 88° + (35/60)° = 88.583°
B = 22° 45' = 22° + (45/60)° = 22.75°
The sum of angles in a triangle = 180°
A + B + C = 180°
C = 180° - (A + B) = 180° - (88.583° + 22.75°) = 68.667°
The sine law is given as
(a/sin A) = (b/sin B) = (c/sin C)
Using the first two terms of the sine law
(a/sin A) = (b/sin B)
a = ?
A = 88.583°
b = 47.7 yd.
B = 22.75°
(a/sin 88.583°) = (47.7/sin 22.75°)
a = (47.7 × sin 88.583°) ÷ sin 22.75°
a = 123.31 yd.
Using the last two terms of the sine law
(b/sin B) = (c/sin C)
b = 47.7 yd.
B = 22.75°
c = ?
C = 68.667°
(47.7/sin 22.75°) = (c/sin 68.667°)
c = (47.7 × sin 68.667°) ÷ sin 22.75°
c = 114.90 yd.
Hope this Helps!!!
