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Doss [256]
2 years ago
13

Pls help mei will give brienliest​

Mathematics
1 answer:
Alisiya [41]2 years ago
6 0

Answer:

y=  4x + -6

Step-by-step explanation:

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Howard’s uncle gave him $885 for his tenth birthday. The money was invested in a savings account with interest compounded at 12%
Stella [2.4K]
Principal Amount = P = $885
Amount Accumulated = A = $3500
Interest rate = r = 12% = 0.12
Compounding period in a year = n = 2
Time in years = t = ?

The formula for compounding is:

A=P(1+ \frac{r}{n})^{t*n}

Using the values, we get:

3500=885(1+ \frac{0.12}{2})^{2*t} \\  \\ 
 \frac{3500}{885} =(1.06)^{2t} \\  \\ 
log(\frac{3500}{885})=log((1.06)^{2t}) \\  \\ 
log(\frac{3500}{885})=2tlog(1.06) \\  \\ 
t= \frac{log(\frac{3500}{885})}{2log(1.06)}  \\  \\  \\ 
t=11.80

This means, it will take him 11.8 or approximately 12 years 
6 0
3 years ago
Determine which ordered pair is the solution to this problem 10=-12y+2x
Fed [463]

Answer:

10-12y+2x

=5.2+6.2y+2yx

=2(5-6y+x)

done

7 0
2 years ago
If altitude BD for ABC falls outside the triangle, what kind of triangle is ABC?
lara [203]

Answer:

Obtuse

Explanation:

Obtuse: The altitude connected to the obtuse vertex is inside the triangle, and the two altitudes connected to the acute vertices are outside the triangle.

7 0
3 years ago
Read 2 more answers
Find the equation of the line that is perpendicular to y = – 1 3 x + 2 and passes though the point (–5, 2)
Fudgin [204]

Answer:

y = 3x + 17

Step-by-step explanation:

8 0
3 years ago
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Consider the vector field ????(x,y,z)=(5z+y)????+(4z+x)????+(4y+5x)????.
Fynjy0 [20]

Answer:

a) 5xz + xy + 4yz

b) 10

Step-by-step explanation:

a) Here F(x,y,z)=(5z+y)i+(4z+x)j+(4y+5x)k

Since the case F  =  ∇f holds, then

∇f = f_xi+f_yj+f_zk = (5z+y)i+(4z+x)j+(4y+5x)k

So, f_x = 5z + y

If we integrate f_x with respect to x, we will get an integration constant C which is also a function that depends to y and z.

Hence,

f = \int f_xdx = 5xz + xy + g(y,z)

Now we need to find g(y,z).

So first let's take the derivative of g(y,z) with respect to y.

f_y = x + g_y(y,z) = 4z + x

Hence, g_y(y,z) = 4z

So now, if we integrate g_y with respect to y to find g(y,z)

g = \int g_ydy = 4yz + C

Thus,

f = 5xz + xy + g(y,z) = 5xz + xy + 4yz + C

And since f(0,0,0)=0, then C=0

Thus,

f = f(x,y,z) = 5xz + xy + 4yz

b) By the Fundamental Theorem of Line Integrals, we know that

\int\limits^a_b F. dr = F[r(b)]-F[r(a)]

Hence,

\int\limits^a_b F. dr = F(1,1,1)-F(0,0,0) =[(5+1+4)-(0+0+0)]=10

8 0
3 years ago
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