-2/(a+b)
Explanation: you are dividing negative two by the sum of a and b so you would put a+b in parentheses as the denominator and then put -2 as the numerator
Answer:
The inequality is -3 < x < 2
The number line is included
Step-by-step explanation:
To express the numbers as an inequality, we have for exclusive numbers the form, [-3, 2] which gives;
-3 < x < 2
We note that an exclusive number (or larger than and lesser than inequality) is represented by an empty in the numbers excluded (for strict equality)
Therefore, we draw a number line with empty circles at number points -3, and 2 as follows;
-4 -3 -2 -1 0 2 1 2 3 4 5
Answer:
C. ![y + \frac{1}{2} = 3(x - 2)](https://tex.z-dn.net/?f=y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%203%28x%20-%202%29)
Step-by-step explanation:
Given
![Point: (2,\frac{-1}{2})](https://tex.z-dn.net/?f=Point%3A%20%20%282%2C%5Cfrac%7B-1%7D%7B2%7D%29)
![Slope: 3](https://tex.z-dn.net/?f=Slope%3A%203)
Required
Equation of line
Let m represents the slope of the line;
m is calculated as thus
![m = \frac{y - y_1}{x - x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By%20-%20y_1%7D%7Bx%20-%20x_1%7D)
![where (x_1,y_1) = (2,\frac{-1}{2})](https://tex.z-dn.net/?f=where%20%28x_1%2Cy_1%29%20%3D%20%282%2C%5Cfrac%7B-1%7D%7B2%7D%29)
![So; x_1 = 2; y_1 = \frac{-1}{2}](https://tex.z-dn.net/?f=So%3B%20x_1%20%3D%202%3B%20y_1%20%3D%20%5Cfrac%7B-1%7D%7B2%7D)
![m = 3](https://tex.z-dn.net/?f=m%20%3D%203)
By substituting the right values in the formula above;
becomes
![3 = \frac{y - \frac{-1}{2}}{x - 2}](https://tex.z-dn.net/?f=3%20%3D%20%5Cfrac%7By%20-%20%5Cfrac%7B-1%7D%7B2%7D%7D%7Bx%20-%202%7D)
Multiply both sides by ![(x - 2)](https://tex.z-dn.net/?f=%28x%20-%202%29)
![3 *(x - 2) = \frac{y - \frac{-1}{2}}{x - 2} *(x - 2)](https://tex.z-dn.net/?f=3%20%2A%28x%20-%202%29%20%3D%20%5Cfrac%7By%20-%20%5Cfrac%7B-1%7D%7B2%7D%7D%7Bx%20-%202%7D%20%2A%28x%20-%202%29)
![3 *(x - 2) = (y - \frac{-1}{2})](https://tex.z-dn.net/?f=3%20%2A%28x%20-%202%29%20%3D%20%28y%20-%20%5Cfrac%7B-1%7D%7B2%7D%29)
![3 *(x - 2) = (y + \frac{1}{2})](https://tex.z-dn.net/?f=3%20%2A%28x%20-%202%29%20%3D%20%28y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%29)
![3(x - 2) = (y + \frac{1}{2})](https://tex.z-dn.net/?f=3%28x%20-%202%29%20%3D%20%28y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%29)
![3(x - 2) = y + \frac{1}{2}](https://tex.z-dn.net/?f=3%28x%20-%202%29%20%3D%20y%20%2B%20%5Cfrac%7B1%7D%7B2%7D)
Reorder
![y + \frac{1}{2} = 3(x - 2)](https://tex.z-dn.net/?f=y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%203%28x%20-%202%29)
Hence, the equation that represents the line is ![y + \frac{1}{2} = 3(x - 2)](https://tex.z-dn.net/?f=y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%203%28x%20-%202%29)
draw a market and place the point (4 ; 1)
then you go on your right : 4 units
and go down : 3 units
you place a second point
and now you can graph the line
Improper because the top is supposed to be lower than the bottom