Answer:It's 12 and 43
Step-by-step explanation:
Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
y = x³ + 3x² - x - 3
0 = x³ + 3x² - x - 3
0 = x²(x) + x²(3) - 1(x) - 1(3)
0 = x²(x + 3) - 1(x + 3)
0 = (x² - 1)(x + 3)
0 = (x² + x - x - 1)(x + 3)
0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
0 = (x(x + 1) - 1(x + 1))(x + 3)
0 = (x - 1)(x + 1)(x + 3)
0 = x - 1 or 0 = x + 1 or 0 = x + 3
+ 1 + 1 - 1 - 1 - 3 - 3
1 = x or -1 = x or -3 = x
Solution Set: {-3, -1, 1}
answer :
3/4
Step-by-step explanation:
it just is.
In the International System of Units (SI), the unit of power is the watt (W), which is equal to one joule per second.
SI unit: watt (W)
In SI base units: kg⋅m2⋅s−3
