Answer:
the answer is 1
Step-by-step explanation:
2^(3/2) - 7 + /-4/
2^(3/2) - 7 + 4
2^(3/2) - 7 + 2^2
2^(3/2) + 2^2 - 7
laws of indices reversed
2^(3/2×2) - 7
2^3 - 7
8 - 7
<u>1</u>
The scale factor is 2 so you would increase each length by 2
Answer:
Inequality Form: m > 7/12
Interval Notation: (7/12, ∞)
Answer:
Average employee [Mean] = 43.6
Step-by-step explanation:
Given:
Interval Number of employee
25-35 20
35-45 7
45-55 8
55-65 15
Total 50
Find:
Average employee [Mean]
Computation:
Interval X[u+l]/2 Number of employee fx
25-35 30 20 600
35-45 40 7 280
45-55 50 8 400
55-65 60 15 900
Total 50 2,180
Average employee [Mean] = Sum of fx / Sum of x
Average employee [Mean] = 2,180 / 50
Average employee [Mean] = 43.6
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0):
Alternative hypothesis (H1):
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0):
Alternative hypothesis (H1):
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no