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WINSTONCH [101]
3 years ago
11

The probability that Renee is on time for a given class is 29 percent. If there are 79 classes during the semester, what is the

best estimate of the number of times out of 79 that Renee is on time to class? Round your answer to the nearest integer.
Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

9

Step-by-step explanation:

vagabundo [1.1K]3 years ago
6 0

Answer:23

Step-by-step explanation:0.29 times 79 since 0.29 equals 22.91 we can estimate that renee will be on time to class about 23 times out of 79

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Julia works for a company selling light bulbs. She sells fluorescent light bulbs for $5 a piece and incandescent light bulbs for
stellarik [79]

The solution to the amount of light bulbs Julia needs to sell to meet her quota is represented by the shaded area in graph X.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the incandescent light bulbs and y represent the fluorescent light bulbs. Therefore:

x + y > 100   (1)

Also:

2x + 5y ≥ 350    (2)

The solution to the amount of light bulbs Julia needs to sell to meet her quota is represented by the shaded area in graph X.

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6 0
2 years ago
Help with multistep problem please! 5(c+4/5)+6=50
Zolol [24]
    5(c + ⁴/₅) + 6 = 50
5(c) + 5(⁴/₅) + 6 = 50
       5c + 4 + 6 = 50
           5c + 10 = 50
           <u>      - 10 - 10</u>
                   <u>5c</u> = <u>40</u>
                    5      5
                     c = 8
3 0
3 years ago
Read 2 more answers
In a state lottery 25 balls numbered from 1 to 25 and placed in machine. 6 numbers randomly drawn. And here is the chart what ca
bonufazy [111]

Answer:

win $5,000: P = 0.0006437

win $50: P = 0.6196

Step-by-step explanation:

To win $5,000, we must have a match of 5 numbers.

So from the 6 numbers, we correcly choose 5 numbers and miss 1 number. The probability of matching or not each of the 6 numbers is:

First number: P = 6/25

Second number: P = 5/24

Third number: P = 4/23

Fourth number: P = 3/22

Fifth number: P = 2/21

Sixth number: P = 19/20 (wrong number)

As the 5 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 5:

c(6,5) = 6!/5! = 6

So the final probability is:

P = 6 * (6/25) * (5/24) * (4/23) * (3/22) * (2/21) * (19/20) = 0.0006437

To find the probability of winning $50, we can do the same steps above, and we need to correcly match 2 numbers, so we have that:

First number: P = 6/25

Second number: P = 5/24

Third number: P = 22/23 (wrong number)

Fourth number: P = 21/22 (wrong number)

Fifth number: P = 20/21 (wrong number)

Sixth number: P = 19/20 (wrong number)

As the 2 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 2:

c(6,2) = 6!/(4!*2!) = 6*5/2 = 15

So the final probability is:

P = 15 * (6/25) * (5/24) * (22/23) * (21/22) * (20/21) * (19/20) = 0.6196

8 0
3 years ago
Is -5x-10 proportional?
Georgia [21]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Figure. ABCD is transformed to A'B'C'D as shown. need help pls
saul85 [17]

Answer:

2nd option

Step-by-step explanation:

4 0
3 years ago
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