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2 years ago

The sales tax rate is 8%. if Yoshi buys a microscope priced at $229, how much tax will he pay?

Mathematics

1 answer:

shtirl [24]2 years ago

3 0

Answer:

247.32

Step-by-step explanation:

229*(108/100)=247.32

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Answer:

Adjacent angles

Step-by-step explanation:

These are adjacent because they share a side

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3 years ago

A store is having a sale in which all items are 20% off. If p is the original price of an item, then the equation p - 0.2p = 0.8

katovenus [111]

Answer:

Answer Expert Verified

We are given that there is a 20% sale in the store. Moreover, the sale price of an item is p - 0.2p, where p is the price of the item. So, we get that, p - 0.2p is equivalent to 0.8p

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2 years ago

3x+5=12-7x solve? Help

horsena [70]

Answer:

3x + 5 = 12 - 7x

⇒ 3x = 12 - 5 - 7x

⇒ 3x = 7 - 7x

⇒ 3x + 7x = 7

⇒ 10x = 7

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⇒<u> x = 0.7</u>

8 0

2 years ago

Stephen evaluated (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). His work is shown below

Maksim231197 [3]

Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated $(6.34\times 10^{-7})(4.5\times 10^3)$ . His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - $(6.34\times 10^{-7})(4.5\times 10^3)$

Step 2 - $(6.34\times 4.5)(10^{-7}\times 10^3)$

Step 3 - $(28.53)(10^{-4})$

Step 4 - $28.53\times 10^{4}$

Error is the step as 4 sign is negative.

So correct step is $28.53\times 10^{-4}$

Step 5 - $28.53\times 10^{3}$

Error is the step as there is 4 in place of 3.

So correct step is $28.53\times 10^{-4}$

The step 4 and 5 describe the errors Stephen made.

7 0

3 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago