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3 years ago

in Google, how should you phrase your search if you want to exclude a certain word from your results(for example,"chocolate")?

1 answer:

3 0

I found this:
ou can exclude words from your search by using the - operator; any word in your query preceded by the - sign is automatically excluded from the search results. Remember to always include a space before the - sign, and none after

I found it here:
http://www.informit.com/articles/article.aspx?p=675274&seqNum=3

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

Write a program to declare a matrix A[][] of order (MXN) where ‘M’ is the number of rows and ‘N’ is the

Liula [17]

Answer:

import java.io.*;

import java.util.Arrays;

class Main {

public static void main(String args[])

throws IOException{

// Set up keyboard input

InputStreamReader in = new InputStreamReader(System.in);

BufferedReader br = new BufferedReader(in);

// Prompt for dimensions MxN of the matrix

System.out.print("M = ");

int m = Integer.parseInt(br.readLine());

System.out.print("N = ");

int n = Integer.parseInt(br.readLine());

// Check if input is within bounds, exit if not

if(m <= 2 || m >= 10 || n <= 2 || n >= 10){

System.out.println("Matrix size out of range.");

return;

}

// Declare the matrix as two-dimensional int array

int a[][] = new int[m][n];

// Prompt for values of the matrix elements

System.out.println("Enter elements of matrix:");

for(int i = 0; i < m; i++){

for(int j = 0; j < n; j++){

a[i][j] = Integer.parseInt(br.readLine());

}

// Output the original matrix

System.out.println("Original Matrix:");

printMatrix(a);

// Sort each row

for(int i = 0; i < m; i++){

Arrays.sort(a[i]);

}

// Print sorted matrix

System.out.println("Matrix after sorting rows:");

printMatrix(a);

}

// Print the matrix elements separated by tabs

public static void printMatrix(int[][] a) {

for(int i = 0; i < a.length; i++){

for(int j = 0; j < a[i].length; j++)

System.out.print(a[i][j] + "\t");

System.out.println();

}

Explanation:

I fixed the mistake in the original code and put comments in to describe each section. The mistake was that the entire matrix was sorted, while only the individual rows needed to be sorted. This even simplifies the program. I also factored out a printMatrix() method because it is used twice.

4 0

3 years ago

What is a good principle to implement when you find yourself attempting to

Maurinko [17]

its less is more A

to much could make it really bad

5 0

4 years ago

Match the OOP concept to its definition.

Alekssandra [29.7K]

Answer:

defines a class in terms of another class = inheritance

inherits the properties of a base class = derived class

provides only essential information to the world = data abstraction

binds data and functions together = encapsulation

Explanation:

6 0

3 years ago

Please help me with this question. I don’t get it

Lelechka [254]

A - they all use microprocessors to compute and store data.

3 0

3 years ago

Read 2 more answers