Answer:
C. layout of each page with its respective elements
Explanation:
A layout of each page with its respective elements will give the client a good idea of the final product and help him confirm his desires/requests towards the creation of the Web site. Most people are visual, especially about things they don't fully understand, so a clear and visual representation is best.
<u>A. Bulleted lists and titles</u>... won't give the idea of the full layout of the Web site.
<u>B. chart depicting</u>.... that's more a tool for the programmer than the client, although user flow is important, it isn't as much as the visual aspect of each page.
<u>D. pictures and screenshots of websites of other florists..</u>. That could be a useful aid on the first contact, but the question implied the Web site is already in progress... so that wouldn't help much.
<u>E. programming code for the website</u>, absolutely not, the client hired Jeremy not to have to deal with that.
Answer:
Your processor might be incompatible with motherboard
Explanation:
One major thing to keep in mind while upgrading a PC hardware is comparability among hardware. If you are using incompatible hardware it can cause issues like this. There are websites available to let you check the compatibility of different components.
As you mentioned you upgraded your cpu and motherboard. Does your motherboard has the correct version of chipset to run new cpu. Do notice if there are any beep sounds when you power up your PC. If you don't hear beeps than your motherboard might be dead.
Answer:
Blank #1 Meetup
Blank#2 MySpace
Explanation:
Blank# 1 Explanation
Meetup is a platform that enables to to seek out (or create!) local meetups. You mark your preferences when you register to this site. Meetup will then inform you of local meet ups that may concern you. The meetups cover a wide range of topics varying from technical issues, professional discussion to hobbies etc. If you do not find topic of your interest, you may set up one and Meetup can inform relevant people who have marked your topic as something that interests them. It's a perfect platform to locally gather people with same interests.
Blank #2 Explanation
MySpace is a platform for social networking. It is a social networking website which offers an engaging, user network of friends, blog, personal profiles, forums, communities, images, songs, and videos.It used to be one of the largest social networking site in the world where people communicate and interact informally.
Answer:
- public class Main {
-
- public static void main (String [] args) {
-
- for(int i = 2; i < 10000; i++){
- if(isPrime1(i)){
- System.out.print(i + " ");
- }
- }
-
- System.out.println();
-
- for(int i = 2; i < 10000; i++){
- if(isPrime2(i)){
- System.out.print(i + " ");
- }
- }
- }
-
- public static boolean isPrime1(int n){
-
- for(int i=2; i <= n/2; i++){
- if(n % i == 0){
- return false;
- }
- }
-
- return true;
- }
-
- public static boolean isPrime2(int n){
-
- for(int i=2; i <= Math.sqrt(n); i++){
- if(n % i == 0){
- return false;
- }
- }
-
- return true;
- }
- }
<u></u>
Explanation:
Firstly, create the first version of method to identify a prime number, isPrime1. This version set the limit of the for loop as n/2. The for loop will iterate through the number from 2 till input n / 2 and check if n is divisible by current value of i. If so, return false to show this is not a prime number (Line 22 - 26). Otherwise it return true to indicate this is a prime number.
In the main program, we call the isPrime1 method by passing the i-index value as an argument within a for-loop that will iterate through the number 2 - 10000 (exclusive). If the method return true, print the current i value). (Line 5 - 9)
The most direct way to ensure all the prime numbers below 10000 are found, is to check the prime status from number 2 - 9999 which is amount to 9998 of numbers.
Next we create a second version of method to check prime, isPrime2 (Line 31 - 40). This version differs from the first version by only changing the for loop condition to i <= square root of n (Line 33). In the main program, we create another for loop and repeatedly call the second version of method (Line 13 - 17). We also get the same output as in the previous version.
