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4 years ago

A 210 Ω resistor is connected to an AC source with E0 = 14.0 V. part a

Physics

1 answer:

Agata [3.3K]4 years ago

7 0

Answer:

(a) 0.0666 A (B) 0.0666 A

Explanation:

(A) We have given emf $E_0=14 V$

The resistance of the circuit = 210 ohm

Emf frequency = 100 Hz there is no use of frequency in case of resistive load as it is independent on the frequency

According to ohm's law $E_0=iR$

So $14=i\times 210$

$i=\frac{14}{210}=0.0666A$

(B) We have given emf $E_0=14 V$

The resistance of the circuit = 210 ohm

Emf frequency = 100 KHz there is no use of frequency in case of resistive load as it is independent on the frequency

According to ohm's law $E_0=iR$

So $14=i\times 210$

$i=\frac{14}{210}=0.0666A$

Note : As the resistive load is independent on the frequency so resistance will be same and so current will also be same in both case

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4 years ago

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