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Anastaziya [24]
4 years ago
5

Two vectors are shown. Which statement best compares the vectors?

Physics
2 answers:
DiKsa [7]4 years ago
8 0

Answer:

B

Explanation:

Because vector Y is longer than vector X

so when you take a magnitude( without minus ) each other

you see that Y>X

Leona [35]4 years ago
6 0

Answer:

Vectors Y has greater magnitude than vector X

Explanation:

The attached figure shows two vectors. A vector have both magnitude and direction.

The length of vector X is less than vector Y. They both are pointing in opposite directions.

The magnitude of a vector is given by :

a = xi +yj

|a|=\sqrt{x^2+y^2}

From the figure, it is clear that the vector Y has greater magnitude than vector X. Hence, the correct option is (B).

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A 21.0 kg shopping cart is moving with a velocity of 6.0 m/s. It strikes a 11.0 kg box that is initially at rest. They stick tog
DedPeter [7]

Answer:

a) 126 kgm/s

b) 0 kgm/s

c) 3.9 m/s

Explanation:

To solve this question, we will use the law of conservation of momentum.

Momentum before collision = momentum after collision

m1v1 + m2v2 = (m1 + m2)v, where

m1 = mass of the shopping cart, 21 kg

m2 = mass of the box, 11 kg

v1 = initial velocity of the shopping cart, 6 m/s

v2 = initial velocity of the box, 0 m/s

v = final velocity of the box+cart

a)

Momentum of the shopping cart before collision = P

P = mv

P = 21 * 6

P = 126 kgm/s = c

b)

Momentum of the box before collision

Like in question a above, the momentum of the box is P

P = mv

P = 11 * 0

P = 0 kgm/s = b

c)

Velocity of the combined shopping cart wreckage after collision is

m1v1 + m2v2 = (m1 + m2)v

(21 * 6) + (11 * 0) = (21 + 11)v

126 + 0 = 32v

32v = 126

v = 126/32

v = 3.9375 m/s, on approximating to 1 decimal place, we have 3.9 m/s and option b as the answer.

Please vote brainliest

8 0
3 years ago
The atomic mass of gold is 0.197 kg/mole. how many moles are in 0.566 kg of gold.
iogann1982 [59]

Explanation:

0.566kg *(1mol/0.197 kg)= 2.87 mol gold

note how the units cancel out, if the units do not cancel out (kg/kg=1) then u did something wrong

7 0
3 years ago
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How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?
7nadin3 [17]
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

7 0
3 years ago
I’m ugly ain’t I ??????
olga55 [171]
Aw don’t say that! I’m sure your beautiful:)
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3 years ago
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