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castortr0y [4]
4 years ago
9

An object is pulled with two forces, 10 N northward and 15 N southward. The direction of the net force is to the An object is pu

lled with two forces, 10 N northward and 15 N southward. The direction of the net force is to the south. north. east. west. none of the above SubmitR

Physics
1 answer:
ValentinkaMS [17]4 years ago
7 0

Answer:

check image

Explanation:

For any question related to newons law of motion first draw the free body diagram(FBD),

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malfutka [58]
<em> I believe the answer is letter C.</em>
8 0
3 years ago
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After release of jet, energy is lost by the engine. How principle of conservation of energy is obeyed in this condition.​
HACTEHA [7]

Answer:

The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another

In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust

The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet

Explanation:

5 0
3 years ago
Forces that act on an object but are not equal in size
mezya [45]
Forces that are equal in size but opposite in direction and do not cause a change in an object's movement are called balanced forces.

forces that aren't equal in size and do cause a change in movement (what it seems like you're asking for) are called UNBALANCED FORCES

so answer (in case that wasn't clear, as I'm tired) : unbalanced forces
7 0
3 years ago
4. What is the electric field strength 1.4 nm from a charge of 4.7 cC?
pentagon [3]

The electric field strength is 2.16\cdot 10^{26} N/C

Explanation:

The strength of the electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge at which the field strength is calculated

For the charge in the problem, we have:

q=4.7 cC = 0.047 C is the charge

r=1.4 nm = 1.4\cdot 10^{-9} m

Therefore, the electric field strength is

E=(8.99\cdot 10^9)\frac{0.047}{(1.4\cdot 10^{-9})^2}=2.16\cdot 10^{26} N/C

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
Two source charges are placed close together. The electric field vectors close to the charges all point toward the charge on the
Leto [7]
B is the correct answer i believe
5 0
3 years ago
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