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AURORKA [14]
3 years ago
6

Write the expression 4+6a/5 -1+3a/4 as a single fraction.

Mathematics
1 answer:
igomit [66]3 years ago
4 0
(21+39a)/20. Because they have to have the same denominator
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Find the factors of<br>y2 + 2y - 35​
baherus [9]

Answer:

(y-5)(y+7)

Step-by-step explanation:

3 0
3 years ago
Please help and explain would I still set this up with law of sine or use cosine
Svetach [21]

You would use the tangent first, because the opposite of 40 would be x and the adjacent would be 30ft

4 0
3 years ago
Write an equation to represent the relationship found in the table
PilotLPTM [1.2K]

Answer:

15= 5x+ 2

Step-by-step explanation:

y= mx+b

y is the intercept,

8 0
2 years ago
If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F .
pashok25 [27]

The measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28

<h3>How to determine the measure of angle EBF?</h3>

The angle measures are given as

If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F

Rewrite the angle measures properly.

This is done, as follows

m∠ABF = (8w − 6)°

m∠ABE = [2(w + 11)]

The measure of angle m∠EBF is calculated as:

m∠ABF = m∠ABE + m∠EBF

Substitute the known values in the above equation

8w - 6 = 2(2w + 11) + m∠EBF

Open the brackets

8w - 6 = 4w + 22 + m∠EBF

Evaluate the like terms

m∠EBF = 4w - 28

Hence, the measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28

Read more about angles at

brainly.com/question/25716982

#SPJ1

5 0
2 years ago
Find the absolute maximum and absolute minimum for f (x )equals x cubed minus 2 x squared minus 4 x plus 2 on the interval 0 les
sineoko [7]

9514 1404 393

Answer:

  • maximum: 2
  • minimum: -6

Step-by-step explanation:

The extrema will be at the ends of the interval or at a critical point within the interval.

The derivative of the function is ...

  f'(x) = 3x² -4x -4 = (x -2)(3x +2)

It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...

  f(0) = 2

  f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6

  f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1

The absolute maximum on the interval is f(0) = 2.

The absolute minimum on the interval is f(2) = -6.

8 0
2 years ago
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