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3 years ago

What is the smallest number that is divisible by 1,2,3,4,5,6,7,8,9 and 10?

1 answer:

8 0

writing each one in prime factors:_
1
2
3
2 * 2
5
2 * 3
7
2* 2 * 2
3 * 3
2 * 5

so the smallest number ( the L.C.M) = 1*2*2*2*3*3*5*7 = 2520

The answer is 2520.

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What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

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The area of sector AOB is what fractional part of the area of circle O?

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I had to look for the figure and here is my answer:

Given the circle attached to this question, the area of the sector AOB is the 60 of the fractional part of the area of the circle O. Since the whole circle is 360, this would be 60/360. To simplify this, we would arrive to the final answer of 1/6. Hope this helps.

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