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kobusy [5.1K]
3 years ago
11

Ming bought 40 pencils and Catherine bought 24. If each package of pencils sold at the store contain the same number of pencils,

what is the largest possible number of pencils in a package?
Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

8

Step-by-step explanation:

To solve this you need to find the largest common factor. The way I did it was by listing out all of the factors of each number, then going through all of them and finding the largest common factor which was 8.

sleet_krkn [62]3 years ago
5 0

Answer:

8 pencils.

Step-by-step explanation:

This is a common, GCF question and the question becomes, what number is the GCF of 40 and 24.

40= 2x2x2x5

24=2x2x2x3

Both share 2x2x2, which is 8 so the largest number of pencils in each pack is 8.

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In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.
tekilochka [14]

If m\angle BAC:m\angle ABC=5:1, then m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.

The sum of the measures of the interior angles of the triangle is always 180°, then

m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.

Since CL is bisector, then

m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.

Consider right triangle ACH. In this triangle

m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.

Now angle HCL has measure

m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.

Answer: m\angle HCL=2m\angle ABC.

6 0
4 years ago
a dozen cupcakes cost $36. last year, the bakery sold 260 dozen cupcake. how much money did the bakery earn selling cupcakes?
Alex777 [14]

Your answer should be 9,360.

You simply take 36 and multiply it by 260

You should get 9,360

Hope you find this helpful!

Brainliest is appreciated!:D

5 0
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