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3 years ago

The probability rolling nine fair dice and getting an even number on all nine dice

1 answer:

swat323 years ago

5 0

The probability is 1/512

This is my work
So you know a die has 3 odd and 3 even so to get a even it is 1/2 chance now you have 9 die so you have to multiply 1/2 by itself 9 times so it can be represented by 1/2^9 (1/2 to the power of 9), which 1*1=1 so just look at the 2. 2^9 is 2*2*2*2*2*2*2*2*2 which is 512. So 1/512 chance they are all even.

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The measure of one angle is 13 less than five times The measure of another angle. The sum of the measure of the two angles is 14

kodGreya [7K]

$\huge\boxed{a=\frac{229}{2};\ \ b=\frac{51}{2}}$

<em>In decimal form, a = 114.5; b = 25.5</em>

We will write this as a system of equations, where $a$ and $b$ are the two angles.

$\left \{ {{a=5b-13} \atop {a+b=140}} \right$

We will use substitution to solve this system. We know what $a$ equals, so we plug that into the second equation.

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Divide both sides by $6$ .

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Now just subtract that from $140$ .

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3 years ago

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alekssr [168]

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2 years ago

Do anyone know how to solve this? need the answer fast.

Nikitich [7]

The value of g^-1(-3) is the value of x that makes g(x) = -3. To find it, we can solve
.. (x +4)/(2x -5) = -3
.. x +4 = -3(2x -5)
.. 7x = 11
.. x = 11/7

The desired value is
.. (3/11)*g^-1(-3)
.. = (3/11)*(11/7)
.. = 3/7

$\frac{3}{11} g^{-1}(-3) = \frac{3}{7}$

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3 years ago