Answer:
if you look up what a exponential looks like it should help
Step-by-step explanation:
The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N
<h3>How to find the Tension in Suspended Cables?</h3>
Resolving forces in the y direction gives us;
T₁ sin 29° + T₂ sin 53° = 210 ------(eq 1)
Resolving forces in the horizontal direction gives;
T₁ cos 29° = T₂ cos 53° ----(eq 2)
T₁ = T₂ cos 53°/cos 29°
Thus;
(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210
0.3336T₂ + 0.7986T₂ = 210
T₂ = 210/1.1322
T₂ = 185.48 N
Thus;
T₁ = 185.48 cos 53°/cos 29°
T₁ = 127.63 N
Read more about Tension in Cables at; brainly.com/question/11653585
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Answer:
8 is the length, and 15 is the height.
8+7 =15
8*15 = 120
Answer:
8/5 or 1 and 3/5
Step-by-step explanation:
substitute then add 4/5 and 4/5.
4.7, because its tenths place is highest
