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3 years ago

Square root of 6 (3- square root of 3)

Mathematics

1 answer:

lesya692 [45]3 years ago

8 0

Answer:

2.44948974278 is the square root of six

Step-by-step explanation:

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1.012 - 0.809 +2.75<br><br>give me the answer

meriva

Answer:

2.953

Step-by-step explanation:

Following the order of operations, work from left to right for addition/subtraction.

Subtraction:

$\begin{array}{r r r r r} ^0\diagup\!\!\!\!1 &. & ^10 & ^0\diagup\!\!\!\!1&^1 2\\ -\quad0&.&8&0&9\\\cline{1-5}0&.&2&0&3\\\cline{1-5} \end{aligned}$

Addition:

$\begin{array}{r c c c r} 0 & . & 2&0&3\\ + \:\:2 &.& 7 & 5\\\cline{1-5}2&.&9&5&3\\\cline{1-5} \end{aligned}$

Therefore, the solution is 2.953

4 0

2 years ago

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the midpoint of AB has coordinates (4, -9). Endpoint A has coordinates (-3,-5). what are the coordinates of B

olchik [2.2K]

The coordinates for other endpoint is (5,-23)

3 0

3 years ago

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Mara writes the expression x + 2(x – 4) – 4x. Which of these expressions are equivalent? Choose the

loris [4]

Answer:

it is number 1. because the answer above is equivalent to number 1

5 0

3 years ago

What is the measure of ∠CED?

harina [27]

You take 90 + 75 = 165 and then 180 - 165 = 15 degrees so that’s your answer

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3 years ago

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Conduct the appropriate hypothesis test and compute the test statistic. A company that produces fishing line undergoes random te

andre [41]

Answer:

Option D) Yes, because the test statistic is -2.01

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 30 pound

Sample mean, $\bar{x}$ = 29.1 pounds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 2 pounds

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30\text{ pounds}\\H_A: \mu < 30\text{ pounds}$

We use one-tailed(left) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29.1 - 30}{\frac{2}{\sqrt{20}} } = -2.012$

Now,

$t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = -1.729$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. Thus, there were enough evidence to conclude that the fishing line breaks with an average force of less than 30 pounds.

Option D) Yes, because the test statistic is -2.01

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4 years ago