Square root of 6 (3- square root of 3)
1 answer:
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Answer:
4sqrt(3)
Step-by-step explanation:
If the triangle is equilateral, the hypotenuse is 2x
We can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
x^2 + 12^2 = (2x)^2
x^2 + 144 = 4x^2
144 = 4x^2 -x^2
144 = 3x^2
48 = x^2
Taking the square root of each side
sqrt(48) = sqrt(x^2)
sqrt(16*3) = x
4 sqrt(3) =x
The correct answer is: [D]: " (-5 
)x − 
" .
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Explanation:
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" -1/2(-3/2x + 6x + 1) −<span> 3x " ;
= (-1/2 * -3/2 x) + (-1/2 * 6x) + (-1/2 * 1) </span>− <span>3x ;
= [ (-1 *-3) /(2*2)] x + (-3x) + (-1/2) ] </span>− <span>3x ;
= [ (3/4)x </span>− 3x − (1/2) ] −<span> 3x ;
= </span>(3/4)x − 3x − (1/2) − 3x ;
= ?? ; → Combine the "like terms" ;
→ "(3/4)x − 3x − 3x " = ?? ;
→ "(3/4)x − 3x = "(-9/4)x";
→ "(-9/4)x − 3x = "(-21/4)x " = " (-5)x " ;
→ The answer is: " (-5)x − " ;
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→ which is:
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→ Answer choice: [D]: " (-5)x − " .
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Explanation:
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" -1/2(-3/2x + 6x + 1) −<span> 3x " ;
= (-1/2 * -3/2 x) + (-1/2 * 6x) + (-1/2 * 1) </span>− <span>3x ;
= [ (-1 *-3) /(2*2)] x + (-3x) + (-1/2) ] </span>− <span>3x ;
= [ (3/4)x </span>− 3x − (1/2) ] −<span> 3x ;
= </span>(3/4)x − 3x − (1/2) − 3x ;
= ?? ; → Combine the "like terms" ;
→ "(3/4)x − 3x − 3x " = ?? ;
→ "(3/4)x − 3x = "(-9/4)x";
→ "(-9/4)x − 3x = "(-21/4)x " = " (-5
→ The answer is: " (-5
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→ which is:
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→ Answer choice: [D]: " (-5
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