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3 years ago

Estimate 49.419-27.276 by first rounding each number to the nearest thousand.

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

22.143

Step-by-step explanation:

49.419-27.276=22.143

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Solve the equation 5(2x -3) = 15

Georgia [21]

Answer:

x=3

Step-by-step explanation:

5(2x-3)=15

10x-15=15

10x=30

x=3

6 0

3 years ago

Read 2 more answers

Can anyone help me pls ( if you can, can you do it on paper and post it with the answer)

Molodets [167]

Answer:

7=a

Step-by-step explanation:

look at image for step by step

4 0

2 years ago

A box of pencils costs $10.The total cost (c) as a function of the number of boxes (b) is expressed as c = f(b) = 10b. What is t

denpristay [2]

Answer:

All positive integers and zero

A is correct

Step-by-step explanation:

A box of pencils costs $10

The total cost (c) as a function of the number of boxes (b) is expressed as

c = f(b) = 10b

The function, f(b) = 10b

b is independent variable and c is dependent variable.

For any function find domain using independent variable.

b represents number of boxes.

Number of boxes neither be negative nor decimal.

Possible value of b: {0,1,2,3,4,5,.......}

All positive integers and zero.

Domain: All positive integers and zero

3 0

3 years ago

Which of the following are best described as lines that meet to form a right

Leona [35]

Answer:

the answer should be C.

Step-by-step explanation:

When two straight lines intersect each other at 90˚ or are perpendicular to each other at the intersection, they form the right angle. A right angle is represented by the symbol ∟.

4 0

2 years ago

Rewrite 2tan3x in terms of tanx

blsea [12.9K]

$2\tan3x=2\tan(2x+x)=\dfrac{2\tan2x+2\tan x}{1-\tan2x\tan x}$

Use the same identity to expand $\tan2x$ .

$\tan2x=\tan(x+x)=\dfrac{\tan x+\tan x}{1-\tan x\tan x}=\dfrac{2\tan x}{1-\tan^2x}$

$\implies2\tan3x=\dfrac{2\dfrac{2\tan x}{1-\tan^2x}+2\tan x}{1-\dfrac{2\tan x}{1-\tan^2x}\tan x}$
$2\tan3x=\dfrac{2\tan x\left(\dfrac2{1-\tan^2x}+1\right)}{1-\dfrac{2\tan^2x}{1-\tan^2x}}$
$2\tan3x=\dfrac{2\tan x\left(2+1-\tan^2x\right)}{1-\tan^2x-2\tan^2x}$
$2\tan3x=\dfrac{2\tan x(3-\tan^2x)}{1-3\tan^2x}$

4 0

3 years ago