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Dimas [21]
3 years ago
14

An Object Speeds Up From 15 m/s to 55 m/s in only 8 s when a force of 100N Is Applied on it. What Is The Mass of the Object?

Mathematics
1 answer:
Kipish [7]3 years ago
6 0

Answer:

500g

Step-by-step explanation:

Because the domula of acceleration is v-u/t so initial velocity is 15 and final velocity is 55 and mass is force * acceleration

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Classify the following triangle. Check all that apply.
Cloud [144]
It has 90 degrees so it's right
And none of the sides are equal so it's scalene
3 0
3 years ago
(FIRST PERSON TO ANSWER GETS BRAINLIEST!!!) A student earned $2500.75 at his summer job making $12.50 per hour. Let h represent
laiz [17]

<u>Answer:</u>

12.50 \space\ h = 2500.75

<u>Step-by-step explanation:</u>

We know from the question that the student earned $12.50 <em>per hour</em>.

Using this information, we can say that if the student worked for <em>h </em>hours, they would make a total of 12.50 × <em>h </em>dollars.

We also know that the total money they earned is $2500.75.

∴ Therefore, we can set up the following equation:

\boxed {12.50 \times h = 2500.75}

From here, if we want to, we can find the number of hours worked by simply making <em>h</em> the subject of the equation and evaluating:

<em>h </em>=<em> </em>\frac{2500.75}{12.50}

  = 200.6 hours

5 0
1 year ago
Read 2 more answers
Which fraction would make this equation true 5×?=6 1/4​
Blizzard [7]

The answer is 1 1/4.

4 0
3 years ago
Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1&gt;3 SUVs per month, where t is time in mon
uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0
1 year ago
If (×)=×-4 wht does f(3) represent​
mario62 [17]

Answer:

you plug in the 3. so you get y= 3-4 which is -1

5 0
3 years ago
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