The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
Answer:
Step-by-step explanation:
If ΔABC ~ ΔDEF
Then their sides must be proportional such that:
=> 
Cross Multiplying
=> x * 6 = 8*3
=> 6x = 24
Dividing both sides by 6
=> x = 4
The slope of RS, RT, and ST are 1/2, -1 and -4 respectively
<h3>Triangle and slopes</h3>
Given the folllowing coordinates R (2,3), S (4,4), and T (5,0) os triangle RST
The formula for calculating the distance is expressed as:
For length RS:
D = √(4-3)²+(4-2)²
RS = √1+4
RS= √5
For length RS:
RT = √(0-3)²+(5-2)²
RT = √9+9
RT= 3√2
For length ST:
D = √(0-4)²+(5-4)²
ST = √16+1
ST= √17
Since all the sides are different, the triangle is a scalene triangle.
For the slope of the sides
For the side RS;
Slope = 4-3/4-2
Slope of RS = 1/2
For the side RT:
Slope = 0-3/5-2
Slope of RT = -3/3 = -1
For the side ST
Slope of ST = 0-4/5-4
Slope of ST = -4/1 = -4
Hence the slope of RS, RT, and ST are 1/2, -1 and -4 respectively
Learn more on slope and distance here: brainly.com/question/2010229
Answer:
prett sure it's b
Step-by-step explanation:
Answer:
A, Standard Deviation, Lowest
Step-by-step explanation:
I got it right lol
