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artcher [175]
3 years ago
10

I need help , help me find the answer to number four please

Mathematics
1 answer:
lakkis [162]3 years ago
4 0
I believe it is H I hope this helps !!!!
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Fanning + medal
lubasha [3.4K]
The Greatest Common Factor of the given expression should be that expression that can divide both. First, factor both expression,
           x^4 = (x³)(x)      and x³ = (x³)(1)
Therefore, both can be factored by x³. The answer is the third choice. 
7 0
3 years ago
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A construction crew is extending the length of the center line on a highway. The length of the line starts out as 6 meters long,
baherus [9]
Gradient of line,m=(17-6)/(20-0)=11/20

finding equation of line using a point (20,17)

y-17=11/20(x-20)
y-17=(11/20x)-11
y=11/20x+(17-11)
y=(11/20)*x+6
4 0
3 years ago
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Un carpintero quiere cortar una plancha de triple y de 1m de largo y 60 cm de ancho, en cuadrados lo más grandes posibles. El ca
Ugo [173]

Answer: 20\ cm

Step-by-step explanation:

The first step to solve the exercise is to make the conversion from meters to centimeters.

Since 1\ m=100\ cm, then the dimensions of the wood board in centimeters are:

Lenght=100\ cm\\\\Width=60\ cm

Now, you must find the Greatest Common Factor (GCF). The steps are:

- Descompose 100 and 60 into their prime factors:

100=2*2*5*5=2^2*5^2\\60=2*2*3*5=2^2*3*5

- Multiply the commons with the lowest exponents:

GCF=2^2*5\\\\GCF=4*5\\\\GCF=20

Therefore, the side lenght of each square must be:

s=20\ cm

7 0
3 years ago
What is the area of the shaded region?
USPshnik [31]

Answer:

Area of the whole rectangle = 11 x 12

= 132 cm^2

Area of the circle = πr^2

= 3.14 x 2 x 2

= 12.56 cm^2

Area of the shaded region = area of rectangle - area of circle

= 132 - 12.56

= 119.44 cm^2

Hope this helps!

7 0
3 years ago
Q5 Q9.) Let theta be an angle in standard position. Name the quadrant in which theta lies
Juliette [100K]
Sine is positive while cotangent is negative. So this must mean cosine is negative since cos/sin = cot. In other words, cotangent is the ratio of cosine over sine.

Because cosine is negative and sine is positive, this places theta in quadrant 2
This is where x < 0 and y > 0. Recall that on the unit circle, x = cos(theta) and y = sin(theta).

The answer is choice B) quadrant II
7 0
3 years ago
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