Ryan is working on the layout of his web page. He needs to figure out where the title, links, text, and images should go. Which
2 answers:
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Answer:
Explanation:
The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"
import java.util.Random;
class Brainly {
public static void main(String[] args) {
UseRandom useRandom = new UseRandom();
boolean youWin = false;
for (int x = 0; x<10; x++) {
int num1 = useRandom.getRandom(6);
int num2 = useRandom.getRandom(6);
if ((num1 + num2) == 10) {
System.out.println("Number 1: " + num1);
System.out.println("Number 2: " + num2);
System.out.println("You Win");
youWin = true;
break;
}
}
if (youWin == false) {
System.out.println("You Lose");
}
}
}
class UseRandom{
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}}
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
