Answer:
Demarcation point
Explanation:
There is point that is set by engineers for the entrance of the cables to provide different services such as Telephone, internet and other utilities. At this point a device has been installed, in which service provider and end users plugin their cables.
Service providers is responsible for any service degradation till this point. After this point user is responsible for any damage. This point is called Demarcation point
.
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
I know of four,
Left-aligned
Center-aligned
right-aligned
justified
Answer:D
Queries are always saved and can therefore be run on the most up-to-date database information
Answer:
C) 1 4 2 / + 1 + 2 + 3 * 2 /
Explanation:
Infix, Postfix and Prefix are 3 different ways of writing expressions which differ in relative placement of operator and operands.
In Infix , operator lies between the operands whereas in postfix operator is written after its operands.
For example: 1 + 2 is infix while 1 2 + is the corresponding postfix expression.
Converting the given infix expression (1 + 4 / 2 + 1 + 2) * 3 / 2 to postfix:
Let (1 + 4 / 2 + 1 + 2) be represented by x.
Converting x to postfix:
(1 + 4 / 2 + 1 + 2) => 1 4 2 / + 1 + 2 + ------------------------- (1)
So the overall infix expression becomes:
x * 3 / 2
Converting it to postfix:
x 3 * 2 /
Replacing the value of x from (1)
1 4 2 / + 1 + 2 + 3 * 2 /
