Answer:
The Kibibyte was developed to take place of the kilobytes in the computer science context where the Kilobyte stands for 1024 bytes. And the Kilobyte interpretation to mean 1024 bytes, conflicts the Standard definition of the prefix kilo or 1000. And the IEC convention for computer international memories was made to define the international standards for electrical, electronic and related technologies.
Explanation:
Please check the answer section.
Answer:
Here the code is given as follows,
Explanation:
Code:-
#include <stdio.h>
int isSorted(int *array, int n) {
if (n <= 1) {
return 1;
} else {
return isSorted(array, n-1) && array[n-2] <= array[n-1];
}
}
int main() {
int arr1[] = {3, 6, 7, 7, 12}, size1 = 5;
int arr2[] = {3, 4, 9, 8}, size2 = 4;
printf("%d\n", isSorted(arr1, size1));
printf("%d\n", isSorted(arr2, size2));
return 0;
}
Output:-
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
Answer:
a.
++score = score + 1
Explanation:
First you have to understand the increment operator;
There are three possible ways to increment the value of variable by 1.
1. <u>post increment</u>
syntax:
name++
it using in expression first then increase the value by 1.
2. <u>Pre increment</u><u> </u>
syntax:
++name
it increase the value by 1 before it using in expression.
3. simple method
name = name +1
In the question,
option 1: ++score = score + 1
it increase the value of score by 2 because their are two increment is used first for (score + 1) and second ++score.
Therefore, the correct option is a.
