Answer:

Step-by-step explanation:




Hope this helps.
Answer:
f(N) = 2+ N/2 + 6N² units of time.
Step-by-step explanation:
Assigning 0 to the variable sum takes one unit of time.
Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have
f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).
Answer:
Im srry can you give me the answers for the question
Step-by-step explanation:
Plz so I can help you
<u>Answer:</u>

<u>Step-by-step explanation:</u>
We are given the following equation and we are supposed to solve y in terms of x. It simpler terms, it means that we have to make y the subject of the equation while x being used in it as it is:

Taking the constant 4 to the side where x is to get:

Multiplying the denominator 3 to the other side of the equation to get:

Isolating y to make it the subject:

Y=4 because y is 4 all the time