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Phantasy [73]
3 years ago
13

How many angles on the diagram have a measure of 70º?

Mathematics
2 answers:
kow [346]3 years ago
6 0
The answer is 39
nwedoni2i2en2ii2pmd2i'2o4i3iji32j2meiio'1'12opejk4rr1oi32i922992299299292299292929292992922920000000201001100010110011001100101010101010110100101011001011010101001010kkmmmmmmccmcmcmcmcmccc  cccc c  c  c 

frutty [35]3 years ago
3 0
I can only see Q. I know this is probably not right, since I am not always right. But, for now, I only see Q!
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Three red rods are 2cm longer than two blue rods. Three blue rods are 2cm longer than four red rods. How long is each rod?
nydimaria [60]

Answer:

The length of each red rod is 10 cm and the length of each blue rod is 14 cm

Step-by-step explanation:

Let

x ----> the length of each red rod in centimeters

y ----> the length of each blue rod in centimeters

we know that

3x=2y+2 ----> equation A

3y=4x+2 ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is the point (10,14)

see the attached figure

therefore

The length of each red rod is 10 cm and the length of each blue rod is 14 cm

4 0
3 years ago
Simplify the expression
8_murik_8 [283]
(√3 + 1)/8 the answer to the question
7 0
3 years ago
Read 2 more answers
What are the solutions of -1 <=x-3<4? help asap ​
viva [34]
I think the answer is -1=x-3<4
4 0
2 years ago
There are 110 calories in 8 ounces of gape juice. How many calories are in 10 ounces of grape juice?
daser333 [38]
In order to solve this problem, we need to set up a proportion.  I am setting the amount of calories in 10 ounces of grape juice equal to x.

\frac{110}{8} = \frac{x}{10}

We begin to solve this by cross multiplying.

8x = 1,100

To finish the problem, we divide both sides by 8.

x = 137.5, so the 10 ounce glass of grape juice will have 137.5 calories.
4 0
3 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
Read 2 more answers
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