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inessss [21]
3 years ago
7

Do the measures of center make​ sense? A. Only the mode makes sense since the data is nominal. B. All the measures of center mak

e sense since the data is numerical. C. Only the​ mean, median, and midrange make sense since the data is nominal. D. Only the​ mean, median, and mode make sense since the data is numerical.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

A. Only the mode makes sense since the data is nominal.

Step-by-step explanation:

Hello!

The objective of the study was to determine if deficiency of carbon dioxide in the soil affects the phenotype of peas.

The variable of study is X: Phenotype of a pea grown in soil with carbon dioxide deficiency.

Possible values of Phenotype codes:

1= smooth-yellow

2= smooth-green

3= wrinkled-yellow

4= wrinkled-green

The absolute frequencies for each phenotype are:

f(1)= 3

f(2)= 4

f(3)= 6

f(4)= 1

n= 14

<u>a) Mean:</u>

X[bar]= (∑xifi)/n= [(1*3)+(2*4)+(3*6)+(4*1)]/14= 33/14= 2.357= 2.36

The average value is always within range of definition of the variable but it does not necessarily correspond to an observation.

<u>b) Median:</u>

To determine the value that corresponds to the median you have to calculate its position:

For even samples the position is:

PosMe= n/2= 14/2= 7

Then you have to arrange the data from least to greatest, in this case, starting from the first category, you have to determine where the seventh observation is within the observed absolute frequencies. The phenotype that corresponds to the 7th observation is 2= smooth-green.

Me= 2= smooth-green.

<u>c) Mode:</u>

The mode corresponds to the most observed category/ value of the variable, i.e. the category with the most observations is 3= wrinkled-yellow

Md= 3= wrinkled-yellow

d) Midrange: (1 + 4)/2= 2.5

e)

As you can see the variable is qualitative and categorical. Even if all central tendency measurements can be calculated, truth is that the only one that shows any valuable information regarding the data set is the mode.

I hope this helps!

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<em><u>The equation to find the length r of the red ribbon is:</u></em>

r = \frac{3b}{2}

<em><u>Solution:</u></em>

Let "b" be the length of blue ribbon

Let "r" be the length of red ribbon

To find: equation for length r of the red ribbon.

The length of the blue ribbon is two - thirds the length of the red ribbon

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\text{Length of blue ribbon } = \frac{2}{3} \times \text{ length of the red ribbon }

Therefore,

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NikAS [45]
The correlation represented is a positive correlation because both variables are increasing. 

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4 years ago
Please answer this for me. i have no idea :( please please please, i am desperate.
marysya [2.9K]
<h3>Answer: B) 60</h3>

================================================

Explanation:

Whenever the angle theta is between 0 and 90, the reference angle is exactly that value.

It's only when you get to other quadrants is when things get a bit tricky. Right now we're in quadrant 1, often written as Q1.

-------------------

Extra info:

  • If theta is between 90 and 180, then the reference angle is 180-theta. This region is Q2
  • If theta is in quadrant 3, between 180 and 270, then the reference angle is theta-180. The order of subtraction is important since x-y is the not the same as y-x.
  • Lastly, if theta is between 270 and 360 (in Q4), then the reference angle is 360-theta.
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wlad13 [49]

Answer:

At midnight, the temperature was 43.7 degrees above 0, and in the morning, it was 3.6 degrees below 0

Step-by-step explanation:

At midnight, the temperature was 43.7°F. In the morning, the temperature was −3.6°F.

We can say that −3.6 lie on the LHS of a number line while 43.7 lie on RHS of the number line and 0 at the mid.

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At midnight, the temperature was 43.7 degrees above 0, and in the morning, it was 3.6 degrees below 0 . Hence, the correct option is (d).

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