Solution:
0.3 × 2.7
Using Distributive property of multiplication with respect to subtraction the value of multiplication of two rationals or two decimals
⇒0.3 × (3-0.3)
⇒ 0.3 × 3 - 0.3 × 0.3
⇒ 0.9 - 0.09
= 0.81
H C F of 0.3 and 2.7 is 0.3.
The Equivalent of product of 0.3 × 2.7 are
1.→0.9 × 0.9
2.→→ 3 × 0.27
Answer: The dimensions are: " 1.5 mi. × ³⁄₁₀ mi. " .
_______________________________________________
{ length = 1.5 mi. ; width = ³⁄₁₀ mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:
A = L * w ;
in which: A = Area = (9/20) mi.² ,
L = Length = ?
w = width = (1/5)*L = (L/5) = ?
________________________________________
A = L * w ; we want to find the dimensions; that is, the values for
"Length (L)" and "width (w)" ;
_______________________________________
Plug in our given values:
_______________________________________
(9/20) mi.² = L * (L/5) ; in which: "w = L/5" ;
→ (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
↔ L² / 5 = 9/20 ;
→ (L² * ? / 5 * ?) = 9/20 ?
→ 20÷5 = 4 ; so; L² *4 = 9 ;
↔ 4 L² = 9 ;
→ Divide EACH side of the equation by "4" ;
→ (4 L²) / 4 = 9/4 ;
______________________________________
to get: → L² = 9/4 ;
Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________
→ ⁺√(L²) = ⁺√(9/4) ;
→ L = (√9) / (√4) ;
→ L = 3/2 ;
→ w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??
→ (3/2)mi. * (3/10)mi. = (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are:
Length = (3/2) mi. ; write as: 1.5 mi.
width = ³⁄₁₀ mi.
___________________________________________________
or; write as: " 1.5 mi. × ³⁄₁₀ mi. " .
___________________________________________________
It’s b
I think…………………………………………..
