_________ is the branch of mathematics dealing primarily with change. a.Trigonometry b.Algebra c.Calculus d.Geometry

1 answer:

7 0

CALCULUS is the branch of mathematics dealing primarily with change. Calculus is the study of how things change. Calculus provides a framework for modelling of systems in which there are changes. It provides means for one to construct simple quantitative models of change and to deduce their consequences.

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Helpppp me pleaseee<br>

mixer [17]

Answer:

1 st questions answer is third option

while the answer of other question is 3

Step-by-step explanation:

2nd qestions explanation

put value of x=2 in equation as x-2=0 from equation

(2)^3-6(2)^2+a2+10=2

8-24+a2+10=0

2a=-18+24

2a=6

a=3

3 0

3 years ago

Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-

Korolek [52]

Since each vector is a member of $\mathbb R^3$ , the vectors will span $\mathbb R^3$ if they form a basis for $\mathbb R^3$ , which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors $c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3$ that gives the zero vector $\mathbf0$ occurs for scalars $c_1=c_2=c_3=0$ .

$c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}$

Solving this, you'll find that $c_1=c_2=c_3=0$ , so the vectors are indeed linearly independent, thus forming a basis for $\mathbb R^3$ and therefore they must span $\mathbb R^3$ .

4 0

3 years ago

The mean length of 6 childrens' big finger is 12.6cm.

malfutka [58]

14.94 cm ( to 2 dec. places )

We require the sum totals of the 2 groups before calculating the mean of all 14

using mean = $\frac{sum}{count}$