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3 years ago

If y’all solve them foe me I’ll love u forever

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

A) Subtract A and C from both sides:

B = 180-A-C

B) Divide both sides by p and t:

r = i /pt

C) Divide both sides by PIh

r^2 = V/pih

Take the square root of both sides:

r = SQRT(V/pih)

D) Subtract ax from both sides:

by = c-ax

Divide both sides by b:

y = (c-ax)/b

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The question is to find the volume. Thanks in advance (repost because no one answered at all)

sergiy2304 [10]

Answer:

48 cm^3

Step-by-step explanation:

You can count the cubes in the top layer and make the reasonable assumption that the other two layers have the same number:

(16 cm^3)×3 = 48 cm^3

_____

<em>Alternate solution</em>

The formula for the volume of a rectangular prism is ...

V = LWH

That is, it is the product of the three dimensions.

V = (4 cm)(4 cm)(3 cm)

V = 48 cm^3

4 0

3 years ago

Element X decays radioactively with a half life of 8 minutes. If there are 480 grams of

Vaselesa [24]

Answer:

40.8 minutes

Step-by-step explanation:

Element X decays radioactively with a half life of 8 minutes. If there are 480 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 14 grams?

The formula to find how long it would take which is the time elapsed is given as:

t = t½ × In(Nt/No)/-In2

t = ?

t½ = 8 minutes

Nt = Amount after the time of decay = 14 grams

No = Original Amount of substances = 480 grams

t = 8 × In(14/480)/-In2

t = 40.796285388407 minutes

Approximately to the nearest tenth = 40.8 minutes

Therefore, it would take the element X, 40.8 minutes to decay to 14 grams

6 0

3 years ago

Angles α and β are angles in standard position such that: α terminates in Quadrant II and sinα = 3/5, β terminates in Quadrant I

777dan777 [17]

We are given

Angles α and β are angles in standard position

and

α terminates in Quadrant II

β terminates in Quadrant I

and we have

$sin(\alpha)=\frac{3}{5}$

we can use triangle and find cos(α)

we get

$cos(\alpha)=-\frac{4}{5}$

and we have

$cos(\beta)=\frac{4}{5}$

we can draw triangle

$sin(\beta)=\frac{3}{5}$

now, we can use formula

$cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)$

now, we can plug values

$cos(\alpha+\beta)=-\frac{4}{5}\times \frac{4}{5}-\frac{3}{5}\times \frac{3}{5}$

now, we can simplify it

$cos(\alpha+\beta)=-\frac{16}{25}-\frac{9}{25}$

$cos(\alpha+\beta)=-\frac{(16+9)}{25}$

$cos(\alpha+\beta)=-\frac{25}{25}$

$cos(\alpha+\beta)=-1$ ...............Answer

3 0

3 years ago

PLEASE Please answer ASAP!!! :)

d1i1m1o1n [39]

Answer: No it is not.

Step-by-step explanation: A rational number is a number that can easily be expressed as a fraction or decimal, and square root of 7 cannot be easily expressed.

6 0

3 years ago

Read 2 more answers

NEED ANSWER!!! “write an equation to find y, the cost of shirts,given x, the number of shirts”?

Romashka-Z-Leto [24]

Answer:

3 x + y=

Step-by-step explanation

7 0

3 years ago