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2 years ago

X(2y + 3z) when x= 8, y= 3, and z= 5/3 HELP!!

Mathematics

1 answer:

Darina [25.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

3(x-8) = -29.7 please solve for x

GrogVix [38]

Answer:

The answer is x= -1.9.

Use the 3 to multiply the number and the letter in the bracket... which is...

3x-24=-29.7.

3x=-29.7+24.

3x=-5.7.

x=-5.7/3.

x=-1.9.

6 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

Christian was 145 cm tall when he was 12 years old. And 3 years later, he became 168.2 cm tall. By what percent did Christian's

Sav [38]

Answer: 16%

Step-by-step explanation:

168.2 - 145 = 23.2

23.2/145 = 0.16

0.16 as a percent is 16%

6 0

3 years ago

Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo

stiks02 [169]

Answer:

(a) Neither

(a) Perpemdicular

Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

$y = -\frac{2}{5}x + 3$

and

$y = \frac{2}{5}x + 7$

An equation written in form: $y=mx + b$ has the slope:

$m \to slope$

So, in both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{2}{5}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{2}{5}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is false in this case, because:

$-\frac{2}{5} * \frac{2}{5} \ne -1$

(b)

$5y + 2x = -10$

and

$-5x + 2y = 4$

Write equations in form: $y=mx + b$

$5y + 2x = -10$

$5y = -2x +10$

Divide by 5

$y = -\frac{2}{5}x +2$

$-5x + 2y = 4$

$2y = 5x + 4$

Divide by 2

$y = \frac{5}{2}x + 2$

In both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{5}{2}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{5}{2}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is true in this case, because:

$-\frac{2}{5} * \frac{5}{2} = -1$

Cancel out 2 and 5

$-1 = -1$

6 0

2 years ago

Given the following prescription formula, what is the ratio strength (nearest whole number) of methylcellulose in the finished p

Mamont248 [21]

Answer:

147

Step-by-step explanation:

Given:

Progesterone = 3.8 g

Glycerin = 7 mL

2% methylcellulose solution 50 mL

Cherry syrup ad = 90 mL

Now,

The total volume of the solution = 7 + 50 + 90 = 147 mL

Also,

2% methylcellulose solution 50 mL is concluded as:

the volume of methylcellulose in the solution is 2% of the total volume of the solution

thus,

volume of methylcellulose = 0.02 × 50 mL = 1 mL

Therefore,

Ratio strength of methylcellulose in the finished product

= $\frac{\textup{volume of methylcellulose}}{\textup{ total volume of the solution}}$

= $\frac{\etxtup{1}}{\textup{ 147}}$

Hence, the answer according to the question is 147

7 0

3 years ago