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castortr0y [4]
3 years ago
9

Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

Mathematics
2 answers:
ser-zykov [4K]3 years ago
8 0
 5k3 - 3k + 7 - (<span>-2k3 + k2 - 9)
= </span> 5k3 - 3k + 7 + 2k3 - k2 + 9
= 7k3 - k2 - 3k + 16
bonufazy [111]3 years ago
3 0

Answer:

7k^3-k^2-3k+16\\

Step-by-step explanation:

we have the expression:

5k^3-3k+7

and we must substract the other expression:

-2k^3+k^2-9

so we will get the following:

5k^3-3k+7-(-2k^3+k^2-9) (we put the minus sign because we are substracting)

So we solve this operation being carefull with the signs:

5k^3-3k+7+2k^3-k^2+9\\

and finally, joining like terms:

7k^3-k^2-3k+16\\

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The perimeter of the isosceles ?ABC with the base BC is equal to 40 cm. Perimeter of the equilateral ?BCD is 45 cm. Find AB and
Juliette [100K]

Answer: AB = 12.5, BC = 15

<u>Step-by-step explanation:</u>

Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC

3BC = 45

<u>÷3   </u>    <u>÷3 </u>

 BC = 15

Perimeter of ΔABC = AB + BC + AC.  Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC

2AB + BC = 40

2AB + 15 = 40

<u>          -15</u>  <u> -15 </u>

2AB       = 25

<u>÷2         </u>   <u>÷2  </u>

      AB  = 12.5

7 0
3 years ago
QUESTION 1 The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.Assume that the driving
GarryVolchara [31]

Answer:

P(X>300)

And we can find this probability with the complement rule:

P(X>300)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X ="driving distance for the top 100 golfers on the PGA tour" and we know that:

X \sim Unif (a=284.7, b=310.6)

And for this case the probability density function is given by:

f(x) =\frac{1}{310.6 -284.7} =0.0386 , 284.7 \leq X \leq 310.6

And the cumulative distribution function is given by:

F(x) =\frac{x-284.7}{310.6-284.7} , 284.7 \leq X \leq 310.6

And we want to find this probability:

P(X>300)

And we can find this probability with the complement rule:

P(X>300)= 1-P(X

6 0
3 years ago
Pamela drove her car 99 kilometers and used 9 liters of fuel. She wants to know how many kilometers (k) she can drive with 12 li
masya89 [10]

Answer:

132 kilometers

Step-by-step explanation:

Given: Pamela drove her car 99 kilometers and used 9 liters of fuel.

To find: Number of kilometers Pamela drove in 12 liters of fuel.

Solution:

It is given that Pamela drove her car 99 kilometers and used 9 liters of fuel. Also the relationship between kilometers and fuel is proportional.

So, let us assume that she can travel x kilometers in 12 liters of fuel.

By proportionality we have,

99:9 :: x:12

\frac{99}{9} =\frac{x}{12}

11=\frac{x}{12}

x=12\times11

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