If (x-2) is a factor of P(x), then what do you think P(x) will be if x = 2? If x is 2 then won't x-2 be zero? And if a factor of of P(x) is zero, won't P(x) be zero, too (regardless of what the other factor is)?
So the "proper value" to test is x=2. If P(2) = 0 then x-2 must be a factor and if P(2) is not zero then x-2 is not a factor is
.3x-x+2=4
I'll leave it up to you so simplify this and find out if x-2 is a factor.
P.S. As I indicated above you use P(2) to see if (x-2) is a factor. P(-2) checks to see if (x-(-2)) or (x+2) is a factor. P(-2) does not check for a factor of (x-2)! Please redo the problem and see what P(2) works out to be!
The answer is: [B]: may.
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Plane <em>ABC</em> <span>and Plane </span><em>BCE </em> <u>MAY</u> be the same plane.
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Note: We can still determine the answer WITHOUT an illustration.
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Explanation:
__________________________________Note that: Two (2) points) determine a line; whereas three (3) points determine a plane.
→ As such, Plane <em>ABC </em>and Plane <em>BCE</em> <u>MAY</u> be the same plane. This would be the case if "<u>Point E</u>" is on Plane <em>ABC</em>. {That is to say, if "<u>Point A</u>" is on Plane <em>BCE </em>}.
→This would be the only "circumstance".
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<span>→ Hence the answer is: [B]: may.</span>
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Answer choice: [A]: "must" ; is incorrect.
It is clearly INCORRECT to say that:
"Plane <em>ABC</em> and Plane <em>BCE</em> "<u>must</u>" be the same plane._____________________________
Answer choice: [C]: "cannot" is clearly incorrect.
As per the example explained above, it is clearly INCORRECT to say that:
""Plane <em>ABC </em>and Plane <em>BCE</em> "<u>cannot</u>" be the same plane.
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Answer:
$40
Step-by-step explanation:
25% is 1/4.
If 10 is 1/4 of the full amount, then you take 10 and multiply by 4 to get the full amount.
10 times 4 equals 40.
Answer:
look below
Step-by-step explanation:
1. napping
2. Union
3. Let's meet at the park for a picnic
4. Put that down right now and don't look at it again
5. race
This might no be right I rushed
