We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
Answer:
<em>x = 2</em>
<em>divide each term by 3 and simplify.</em>
Answer:
1/3
Step-by-step explanation:
if you move up 1 over three, the line intersects the graph
1/8 of all=mystery
mystery=3
'of' means multiply
therefor
1/8 times all=3
multiply both sides by 8/1 to clear fracion
all=24
